Optimal. Leaf size=257 \[ \frac{f^2 p \text{PolyLog}\left (2,\frac{e x^n}{d}+1\right )}{n}+\frac{f^2 \log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )}{n}-\frac{f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )}{n}-\frac{g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )}{4 n}+\frac{e^2 f g p \log \left (d+e x^n\right )}{d^2 n}-\frac{e^2 f g p \log (x)}{d^2}+\frac{e^2 g^2 p x^{-2 n}}{8 d^2 n}-\frac{e^3 g^2 p x^{-n}}{4 d^3 n}+\frac{e^4 g^2 p \log \left (d+e x^n\right )}{4 d^4 n}-\frac{e^4 g^2 p \log (x)}{4 d^4}-\frac{e f g p x^{-n}}{d n}-\frac{e g^2 p x^{-3 n}}{12 d n} \]
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Rubi [A] time = 0.317214, antiderivative size = 257, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 9, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2475, 263, 266, 43, 2416, 2395, 44, 2394, 2315} \[ \frac{f^2 p \text{PolyLog}\left (2,\frac{e x^n}{d}+1\right )}{n}+\frac{f^2 \log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )}{n}-\frac{f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )}{n}-\frac{g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )}{4 n}+\frac{e^2 f g p \log \left (d+e x^n\right )}{d^2 n}-\frac{e^2 f g p \log (x)}{d^2}+\frac{e^2 g^2 p x^{-2 n}}{8 d^2 n}-\frac{e^3 g^2 p x^{-n}}{4 d^3 n}+\frac{e^4 g^2 p \log \left (d+e x^n\right )}{4 d^4 n}-\frac{e^4 g^2 p \log (x)}{4 d^4}-\frac{e f g p x^{-n}}{d n}-\frac{e g^2 p x^{-3 n}}{12 d n} \]
Antiderivative was successfully verified.
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Rule 2475
Rule 263
Rule 266
Rule 43
Rule 2416
Rule 2395
Rule 44
Rule 2394
Rule 2315
Rubi steps
\begin{align*} \int \frac{\left (f+g x^{-2 n}\right )^2 \log \left (c \left (d+e x^n\right )^p\right )}{x} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (f+\frac{g}{x^2}\right )^2 \log \left (c (d+e x)^p\right )}{x} \, dx,x,x^n\right )}{n}\\ &=\frac{\operatorname{Subst}\left (\int \left (\frac{g^2 \log \left (c (d+e x)^p\right )}{x^5}+\frac{2 f g \log \left (c (d+e x)^p\right )}{x^3}+\frac{f^2 \log \left (c (d+e x)^p\right )}{x}\right ) \, dx,x,x^n\right )}{n}\\ &=\frac{f^2 \operatorname{Subst}\left (\int \frac{\log \left (c (d+e x)^p\right )}{x} \, dx,x,x^n\right )}{n}+\frac{(2 f g) \operatorname{Subst}\left (\int \frac{\log \left (c (d+e x)^p\right )}{x^3} \, dx,x,x^n\right )}{n}+\frac{g^2 \operatorname{Subst}\left (\int \frac{\log \left (c (d+e x)^p\right )}{x^5} \, dx,x,x^n\right )}{n}\\ &=-\frac{g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )}{4 n}-\frac{f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )}{n}+\frac{f^2 \log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )}{n}-\frac{\left (e f^2 p\right ) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{e x}{d}\right )}{d+e x} \, dx,x,x^n\right )}{n}+\frac{(e f g p) \operatorname{Subst}\left (\int \frac{1}{x^2 (d+e x)} \, dx,x,x^n\right )}{n}+\frac{\left (e g^2 p\right ) \operatorname{Subst}\left (\int \frac{1}{x^4 (d+e x)} \, dx,x,x^n\right )}{4 n}\\ &=-\frac{g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )}{4 n}-\frac{f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )}{n}+\frac{f^2 \log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )}{n}+\frac{f^2 p \text{Li}_2\left (1+\frac{e x^n}{d}\right )}{n}+\frac{(e f g p) \operatorname{Subst}\left (\int \left (\frac{1}{d x^2}-\frac{e}{d^2 x}+\frac{e^2}{d^2 (d+e x)}\right ) \, dx,x,x^n\right )}{n}+\frac{\left (e g^2 p\right ) \operatorname{Subst}\left (\int \left (\frac{1}{d x^4}-\frac{e}{d^2 x^3}+\frac{e^2}{d^3 x^2}-\frac{e^3}{d^4 x}+\frac{e^4}{d^4 (d+e x)}\right ) \, dx,x,x^n\right )}{4 n}\\ &=-\frac{e g^2 p x^{-3 n}}{12 d n}+\frac{e^2 g^2 p x^{-2 n}}{8 d^2 n}-\frac{e f g p x^{-n}}{d n}-\frac{e^3 g^2 p x^{-n}}{4 d^3 n}-\frac{e^2 f g p \log (x)}{d^2}-\frac{e^4 g^2 p \log (x)}{4 d^4}+\frac{e^2 f g p \log \left (d+e x^n\right )}{d^2 n}+\frac{e^4 g^2 p \log \left (d+e x^n\right )}{4 d^4 n}-\frac{g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )}{4 n}-\frac{f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )}{n}+\frac{f^2 \log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )}{n}+\frac{f^2 p \text{Li}_2\left (1+\frac{e x^n}{d}\right )}{n}\\ \end{align*}
Mathematica [A] time = 0.569967, size = 188, normalized size = 0.73 \[ -\frac{-24 f^2 \left (p \text{PolyLog}\left (2,\frac{e x^n}{d}+1\right )+\log \left (-\frac{e x^n}{d}\right ) \log \left (c \left (d+e x^n\right )^p\right )\right )+24 f g x^{-2 n} \log \left (c \left (d+e x^n\right )^p\right )+6 g^2 x^{-4 n} \log \left (c \left (d+e x^n\right )^p\right )+\frac{e g^2 p \left (d x^{-3 n} \left (2 d^2-3 d e x^n+6 e^2 x^{2 n}\right )-6 e^3 \log \left (d+e x^n\right )+6 e^3 n \log (x)\right )}{d^4}+\frac{24 e f g p \left (-e \log \left (d+e x^n\right )+d x^{-n}+e n \log (x)\right )}{d^2}}{24 n} \]
Antiderivative was successfully verified.
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Maple [C] time = 5.238, size = 755, normalized size = 2.9 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{2 \, d^{2} e g^{2} p x^{n} + 6 \, d^{3} g^{2} \log \left (c\right ) + 12 \,{\left (d^{3} f^{2} n^{2} p \log \left (x\right )^{2} - 2 \, d^{3} f^{2} n \log \left (c\right ) \log \left (x\right )\right )} x^{4 \, n} + 6 \,{\left (4 \, d^{2} e f g p + e^{3} g^{2} p\right )} x^{3 \, n} - 3 \,{\left (d e^{2} g^{2} p - 8 \, d^{3} f g \log \left (c\right )\right )} x^{2 \, n} - 6 \,{\left (4 \, d^{3} f^{2} n x^{4 \, n} \log \left (x\right ) - 4 \, d^{3} f g x^{2 \, n} - d^{3} g^{2}\right )} \log \left ({\left (e x^{n} + d\right )}^{p}\right )}{24 \, d^{3} n x^{4 \, n}} + \int \frac{4 \, d^{4} f^{2} n p \log \left (x\right ) - 4 \, d^{2} e^{2} f g p - e^{4} g^{2} p}{4 \,{\left (d^{3} e x x^{n} + d^{4} x\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.18595, size = 590, normalized size = 2.3 \begin{align*} -\frac{24 \, d^{4} f^{2} n p x^{4 \, n} \log \left (x\right ) \log \left (\frac{e x^{n} + d}{d}\right ) + 24 \, d^{4} f^{2} p x^{4 \, n}{\rm Li}_2\left (-\frac{e x^{n} + d}{d} + 1\right ) + 2 \, d^{3} e g^{2} p x^{n} + 6 \, d^{4} g^{2} \log \left (c\right ) + 6 \,{\left (4 \, d^{3} e f g + d e^{3} g^{2}\right )} p x^{3 \, n} - 6 \,{\left (4 \, d^{4} f^{2} n \log \left (c\right ) -{\left (4 \, d^{2} e^{2} f g + e^{4} g^{2}\right )} n p\right )} x^{4 \, n} \log \left (x\right ) - 3 \,{\left (d^{2} e^{2} g^{2} p - 8 \, d^{4} f g \log \left (c\right )\right )} x^{2 \, n} + 6 \,{\left (4 \, d^{4} f g p x^{2 \, n} + d^{4} g^{2} p -{\left (4 \, d^{4} f^{2} n p \log \left (x\right ) +{\left (4 \, d^{2} e^{2} f g + e^{4} g^{2}\right )} p\right )} x^{4 \, n}\right )} \log \left (e x^{n} + d\right )}{24 \, d^{4} n x^{4 \, n}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f + \frac{g}{x^{2 \, n}}\right )}^{2} \log \left ({\left (e x^{n} + d\right )}^{p} c\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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